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-7y^2-5y+10=0
a = -7; b = -5; c = +10;
Δ = b2-4ac
Δ = -52-4·(-7)·10
Δ = 305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{305}}{2*-7}=\frac{5-\sqrt{305}}{-14} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{305}}{2*-7}=\frac{5+\sqrt{305}}{-14} $
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